‘factor(x, exclude = NULL)’ applied to a factor without ‘NA’s is a no-operation unless there are unused levels: in that case, a factor with the reduced level set is returned. ‘as.factor’ coerces its argument to a factor.

Feb 25, 2013 · Is the general rule to use factor when the variable being used to determine the shape/size/colour is discrete, and not continuous? Or is there another use of factor in this context? It seems like the first command can be made like the second with the right legend, even without factor . thanks.

May 3, 2013 · GGPLOT with lines for factor on x-axis data not working. 1. Line graph with multiple factors in ggplot2. 2.

This results in a boxplot with 4, 6, and 8 cylinders as the x axis factors. What I would like to do is change those x axis factors. For example, how could I change 4 to "Four Cyl" without editing the original data?

The important point here is the order of the factor levels. The order in the levels is also the order in the plot. You can use rev to reverse the order of the levels like this (note that I just reorder one column in a data.frame):

Oct 10, 2014 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.

You can do it with ggplot2, using facets.When I read "I want to create a plot where the data points are grouped as defined by the factor", the first thing that came to my mind was facets.

Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.

But annoyingly, there is nothing to handle the factor -> numeric conversion. As an extension of Joshua Ulrich's answer, I would suggest to overcome this omission with the definition of your own idiomatic function: as.double.factor <- function(x) {as.numeric(levels(x))[x]}

Feb 4, 2019 · Write $$ x^n+1 = \frac{x^{2n}-1}{x^n-1} $$ The factorization over $\mathbb Q$ of the polynomials in the fraction are given by cyclotomic polynomials. Share Cite